4.9x^2-100x+510=0

Solution for 4.9x^2-100x+510=0 equation:

4.9x^2-100x+510=0

a = 4.9; b = -100; c = +510;
Δ = b2-4ac
Δ = -1002-4·4.9·510
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-2}{2*4.9}=\frac{98}{9.8}
=10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+2}{2*4.9}=\frac{102}{9.8}
=10+4/9.8
$